Marbleton is a town in Sublette County, Wyoming, United States. The population was 720 at the 2000 census. According to the United States Census Bureau, the town has a total area of 0.7square miles (1.8Square kilometers), all of it land. As of the census of 2000, there were 720 people, 268 households, and 201 families residing in the town. The population density was 1,060.8 people per square mile (408.8Square kilometers). There were 310 housing units at an average density of 456.7per square mile (176.0Square kilometers).